Reverse number pattern program in python using while loop
- Iterate over the list in reverse using ‘for’ loop : loop helps us always while iterating through something. In python, we have range () function to iterate. We can define this method as range ( [start], stop [, step]). start: It is the starting index of the sequence. stop: The range will run till this index, but it will not include this index.
- OOP in Python (argparse) Create a class. Create instance of class. Import module containing class. Import class from module. Initialize instance (not a constructor) Self is the instance. Init uses same name as attribute and getters. Initialize an instance - (not a constructor), attributes and getters.
- Generate a series of 1 to n Numbers. Develop a series of odd numbers from 1 to n. Print a series of numbers divisible by 3 from 1 to n. Create a series of square numbers from 1 to n. Display all multiples of 4 starting from 11 to 100. In the next section of Python Loop Programs for Class 11 you will get programs based on reverse number.
- Let's see Python program to print inverted star pattern: # python 3 code to print inverted star. # pattern. # n is the number of rows in which. # star is going to be printed. n=11. # i is going to be enabled to. # range between n-i t 0 with a. # decrement of 1 with each iteration.
- Print Star Pattern in Python. You can write this program using for loop and while loop. Follow same concept like C programming only change syntax.
- Reverse number pattern in Cpp using while loop. In this tutorial, we will discuss Reverse number pattern in Cpp using while loop. In C++ language, we can use for loop, while loop, do-while loop to display various number, star, alphabet and binary number patterns. In this topic, we demonstrate how to display some reversed number patterns using the nested while loop in Cpp language.
- In this program, while loop is used to reverse a number as given in the following steps: First, the remainder of the num divided by 10 is stored in the variable digit.Now, the digit contains the last digit of num, i.e. 4. digit is then added to the variable reversed after multiplying it by 10. Multiplication by 10 adds a new place in the reversed number.
- Problem Solution. 1. Take the value of the integer and store in a variable. 2. Using a while loop, get each digit of the number and store the reversed number in another variable. 3. Print the reverse of the number. 4. Exit.
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Problem Solution. 1. Take the value of the integer and store in a variable. 2. Using a while loop, get each digit of the number and store the reversed number in another variable. 3. Print the reverse of the number. 4. Exit. 3. Using a while loop, get each digit of the number and store the reversed number in another variable. 4. Check if the reverse of the number is equal to the one in the temporary variable. 5. Print the final result. 6. Exit.
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